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简答题求ab之间等效电阻Rab
  • 由对称得:Rab=(R/2)+(R/4)+(R/4)+(R/2)=1.5R
    Rab=9+3+(9+3)//(3+3)=16欧
    Rab=R2+(1-u)R1
    Rab=2+(1+1)//2=3欧
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