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简答题 如图，为复合水准测量，采用视线高法计算各测站视线高，和各转点的高程。
  • 第一测站视线高H1=HA+a1=65.116+1.803=66.919m
    P1高程Hp1=H-b1=66.919-1.226=65.693m
    H2=Hp1+a2=65.693+1.684=67.377m
    Hp2=H2-b2=67.377-1.230=66.147m
    H3=Hp2+a3=66.147+1.578=67.725m
    Hp3=H3-b3=67.725-1.191=66.534m
    H4=Hp3+a4=66.534+1.540=68.074
    Hp4=H4-b4=68.014-1.196=66.878m
    H5=Hp4+a5=66.878+0.892=67.77
    Hp5=H5-b5=67.77-1.514=66.256=HB
    Σa=7.497Σb=6.357
    Σa-Σb=+1.140
    HB-HA=.66.256-65.116=+1.140
    ∴Σa-Σb=HB-HA
    测点视线高为A 为66.919,P1为67.377,P2为67.127,P3为68.074,P4为67,770,高程P165.693,P2这66.147,P366.534 ,P466.878,B点为66.256。

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